Question
In the figure, BCDE is a parallelogram and CFG is a triangle. FH is a straight line and JH is parallel to ED. ∠EHJ = 113° and ∠BEH = 129°. Find ∠BCD.
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In the figure, BCDE is a parallelogram and CFG is a triangle. FH is a straight line and JH is parallel to ED. ∠EHJ = 113° and ∠BEH = 129°. Find ∠BCD.