GHJK is a square. VUJ and HUK are straight lines. HG = HV and ∠UHV = 15°. Find
- ∠HGV
- ∠KJV
.
(a)
∠GHK = 45° (Right angle)
∠GHV
= ∠GHK - ∠UHV
= 45° - 15°
= 30°
∠HGV
= (180° - ∠GHV) ÷ 2
= (180° - 30°) ÷ 2
= 150° ÷ 2
= 75° (Isosceles triangle)
(b)
HG = HV = HJ
VHJ is an isosceles triangle.
∠HVJ = ∠HJV (Isosceles triangle)
∠HJV
= (180° - ∠KHJ - ∠UHV) ÷ 2
= (180° - 45° -15°) ÷ 2
= 120° ÷ 2
= 60°
∠KJV
= ∠HJK - ∠HJV
= 90° - 60°
= 30°
Answer(s): (a) 75°; (b) 30°
