JKLM is a square. WVL and KVM are straight lines. KJ = KW and ∠VKW = 11°. Find
- ∠KJW
- ∠MLW
.
(a)
∠JKM = 45° (Right angle)
∠JKW
= ∠JKM - ∠VKW
= 45° - 11°
= 34°
∠KJW
= (180° - ∠JKW) ÷ 2
= (180° - 34°) ÷ 2
= 146° ÷ 2
= 73° (Isosceles triangle)
(b)
KJ = KW = KL
WKL is an isosceles triangle.
∠KWL = ∠KLW (Isosceles triangle)
∠KLW
= (180° - ∠MKL - ∠VKW) ÷ 2
= (180° - 45° -11°) ÷ 2
= 124° ÷ 2
= 62°
∠MLW
= ∠KLM - ∠KLW
= 90° - 62°
= 28°
Answer(s): (a) 73°; (b) 28°
