HJKL is a square. VUK and JUL are straight lines. JH = JV and ∠UJV = 13°. Find
- ∠JHV
- ∠LKV
.
(a)
∠HJL = 45° (Right angle)
∠HJV
= ∠HJL - ∠UJV
= 45° - 13°
= 32°
∠JHV
= (180° - ∠HJV) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
JH = JV = JK
VJK is an isosceles triangle.
∠JVK = ∠JKV (Isosceles triangle)
∠JKV
= (180° - ∠LJK - ∠UJV) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠LKV
= ∠JKL - ∠JKV
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
