EFGH is a square. TSG and FSH are straight lines. FE = FT and ∠SFT = 13°. Find
- ∠FET
- ∠HGT
.
(a)
∠EFH = 45° (Right angle)
∠EFT
= ∠EFH - ∠SFT
= 45° - 13°
= 32°
∠FET
= (180° - ∠EFT) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
FE = FT = FG
TFG is an isosceles triangle.
∠FTG = ∠FGT (Isosceles triangle)
∠FGT
= (180° - ∠HFG - ∠SFT) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠HGT
= ∠FGH - ∠FGT
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
