CDEF is a square. GFE and DFF are straight lines. DC = DG and ∠FDG = 13°. Find
- ∠DCG
- ∠FEG
.
(a)
∠CDF = 45° (Right angle)
∠CDG
= ∠CDF - ∠FDG
= 45° - 13°
= 32°
∠DCG
= (180° - ∠CDG) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
DC = DG = DE
GDE is an isosceles triangle.
∠DGE = ∠DEG (Isosceles triangle)
∠DEG
= (180° - ∠FDE - ∠FDG) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠FEG
= ∠DEF - ∠DEG
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
