VWXY is a square. KJX and WJY are straight lines. WV = WK and ∠JWK = 13°. Find
- ∠WVK
- ∠YXK
.
(a)
∠VWY = 45° (Right angle)
∠VWK
= ∠VWY - ∠JWK
= 45° - 13°
= 32°
∠WVK
= (180° - ∠VWK) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
WV = WK = WX
KWX is an isosceles triangle.
∠WKX = ∠WXK (Isosceles triangle)
∠WXK
= (180° - ∠YWX - ∠JWK) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠YXK
= ∠WXY - ∠WXK
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
