UVWX is a square. LKW and VKX are straight lines. VU = VL and ∠KVL = 13°. Find
- ∠VUL
- ∠XWL
.
(a)
∠UVX = 45° (Right angle)
∠UVL
= ∠UVX - ∠KVL
= 45° - 13°
= 32°
∠VUL
= (180° - ∠UVL) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
VU = VL = VW
LVW is an isosceles triangle.
∠VLW = ∠VWL (Isosceles triangle)
∠VWL
= (180° - ∠XVW - ∠KVL) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠XWL
= ∠VWX - ∠VWL
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
