JKLM is a square. HGL and KGM are straight lines. KJ = KH and ∠GKH = 11°. Find
- ∠KJH
- ∠MLH
.
(a)
∠JKM = 45° (Right angle)
∠JKH
= ∠JKM - ∠GKH
= 45° - 11°
= 34°
∠KJH
= (180° - ∠JKH) ÷ 2
= (180° - 34°) ÷ 2
= 146° ÷ 2
= 73° (Isosceles triangle)
(b)
KJ = KH = KL
HKL is an isosceles triangle.
∠KHL = ∠KLH (Isosceles triangle)
∠KLH
= (180° - ∠MKL - ∠GKH) ÷ 2
= (180° - 45° -11°) ÷ 2
= 124° ÷ 2
= 62°
∠MLH
= ∠KLM - ∠KLH
= 90° - 62°
= 28°
Answer(s): (a) 73°; (b) 28°
