RSTU is a square. JHT and SHU are straight lines. SR = SJ and ∠HSJ = 11°. Find
- ∠SRJ
- ∠UTJ
.
(a)
∠RSU = 45° (Right angle)
∠RSJ
= ∠RSU - ∠HSJ
= 45° - 11°
= 34°
∠SRJ
= (180° - ∠RSJ) ÷ 2
= (180° - 34°) ÷ 2
= 146° ÷ 2
= 73° (Isosceles triangle)
(b)
SR = SJ = ST
JST is an isosceles triangle.
∠SJT = ∠STJ (Isosceles triangle)
∠STJ
= (180° - ∠UST - ∠HSJ) ÷ 2
= (180° - 45° -11°) ÷ 2
= 124° ÷ 2
= 62°
∠UTJ
= ∠STU - ∠STJ
= 90° - 62°
= 28°
Answer(s): (a) 73°; (b) 28°
