UVWX is a square. XWW and VWX are straight lines. VU = VX and ∠WVX = 13°. Find
- ∠VUX
- ∠XWX
.
(a)
∠UVX = 45° (Right angle)
∠UVX
= ∠UVX - ∠WVX
= 45° - 13°
= 32°
∠VUX
= (180° - ∠UVX) ÷ 2
= (180° - 32°) ÷ 2
= 148° ÷ 2
= 74° (Isosceles triangle)
(b)
VU = VX = VW
XVW is an isosceles triangle.
∠VXW = ∠VWX (Isosceles triangle)
∠VWX
= (180° - ∠XVW - ∠WVX) ÷ 2
= (180° - 45° -13°) ÷ 2
= 122° ÷ 2
= 61°
∠XWX
= ∠VWX - ∠VWX
= 90° - 61°
= 29°
Answer(s): (a) 74°; (b) 29°
