VWXY is a square. UTX and WTY are straight lines. WV = WU and ∠TWU = 11°. Find
- ∠WVU
- ∠YXU
.
(a)
∠VWY = 45° (Right angle)
∠VWU
= ∠VWY - ∠TWU
= 45° - 11°
= 34°
∠WVU
= (180° - ∠VWU) ÷ 2
= (180° - 34°) ÷ 2
= 146° ÷ 2
= 73° (Isosceles triangle)
(b)
WV = WU = WX
UWX is an isosceles triangle.
∠WUX = ∠WXU (Isosceles triangle)
∠WXU
= (180° - ∠YWX - ∠TWU) ÷ 2
= (180° - 45° -11°) ÷ 2
= 124° ÷ 2
= 62°
∠YXU
= ∠WXY - ∠WXU
= 90° - 62°
= 28°
Answer(s): (a) 73°; (b) 28°
