FGHJ is a square. TSH and GSJ are straight lines. GF = GT and ∠SGT = 11°. Find
- ∠GFT
- ∠JHT
.
(a)
∠FGJ = 45° (Right angle)
∠FGT
= ∠FGJ - ∠SGT
= 45° - 11°
= 34°
∠GFT
= (180° - ∠FGT) ÷ 2
= (180° - 34°) ÷ 2
= 146° ÷ 2
= 73° (Isosceles triangle)
(b)
GF = GT = GH
TGH is an isosceles triangle.
∠GTH = ∠GHT (Isosceles triangle)
∠GHT
= (180° - ∠JGH - ∠SGT) ÷ 2
= (180° - 45° -11°) ÷ 2
= 124° ÷ 2
= 62°
∠JHT
= ∠GHJ - ∠GHT
= 90° - 62°
= 28°
Answer(s): (a) 73°; (b) 28°
