Question
P6.AN.NK.17051715-A1
In the figure, ZABC is a parallelogram and BDE is an isosceles triangle. ADCE is a straight line. ∠AZC = 103°, ∠BCD = 58° and ∠CBE = 13°. Find ∠ABD.
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Primary 6 ANGLES P6.AN.NK.17051715

19 May 2024, 03:02 AM

In the figure, ZABC is a parallelogram and BDE is an isosceles triangle. ADCE is a straight line. ∠AZC = 103°, ∠BCD = 58° and ∠CBE = 13°. Find ∠ABD.
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