Question
In the figure, DEFG is a parallelogram and FHJ is an isosceles triangle. EHGJ is a straight line. ∠EDG = 101°, ∠FGH = 57° and ∠GFJ = 11°. Find ∠EFH.
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In the figure, DEFG is a parallelogram and FHJ is an isosceles triangle. EHGJ is a straight line. ∠EDG = 101°, ∠FGH = 57° and ∠GFJ = 11°. Find ∠EFH.