Question
In the figure, EFGH is a parallelogram and GJK is an isosceles triangle. FJHK is a straight line. ∠FEH = 101°, ∠GHJ = 60° and ∠HGK = 16°. Find ∠FGJ.
3 m

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In the figure, EFGH is a parallelogram and GJK is an isosceles triangle. FJHK is a straight line. ∠FEH = 101°, ∠GHJ = 60° and ∠HGK = 16°. Find ∠FGJ.