Question
P6.AN.NK.17051715-A1
In the figure, EFGH is a parallelogram and GJK is an isosceles triangle. FJHK is a straight line. ∠FEH = 103°, ∠GHJ = 55° and ∠HGK = 14°. Find ∠FGJ.
3 m
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Primary 6 ANGLES P6.AN.NK.17051715

30 Apr 2024, 02:37 AM

In the figure, EFGH is a parallelogram and GJK is an isosceles triangle. FJHK is a straight line. ∠FEH = 103°, ∠GHJ = 55° and ∠HGK = 14°. Find ∠FGJ.
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