Question
In the figure, CDEF is a parallelogram and EGH is an isosceles triangle. DGFH is a straight line. ∠DCF = 101°, ∠EFG = 52° and ∠FEH = 11°. Find ∠DEG.
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In the figure, CDEF is a parallelogram and EGH is an isosceles triangle. DGFH is a straight line. ∠DCF = 101°, ∠EFG = 52° and ∠FEH = 11°. Find ∠DEG.