Question
P6.AN.NK.17051715-A1
In the figure, ZABC is a parallelogram and BDE is an isosceles triangle. ADCE is a straight line. ∠AZC = 101°, ∠BCD = 54° and ∠CBE = 11°. Find ∠ABD.
3 m
∑

Click ∑ button first when a symbol is required. X

Symbols

Enter the numerator and denominator


Enter value


2
Question Solution

1-minute grace period



When you click the Next button, you will be given 1-minute grace period to decide whether to do the next question type.

The question will be marked as incorrect if you exceed 1 minute and leave the question page.

Click the Back button instead if you would like to return to the topic page.

STUDENT

Primary 6 ANGLES P6.AN.NK.17051715

18 May 2024, 11:45 AM

In the figure, ZABC is a parallelogram and BDE is an isosceles triangle. ADCE is a straight line. ∠AZC = 101°, ∠BCD = 54° and ∠CBE = 11°. Find ∠ABD.
Navigations
Contact Us
Members
Links