In the figure, ZAD and CAB are right-angled triangles. DA is parallel to CB. Find
- ∠ABC
- ∠ADC
(a)
∠CAD
= 360° - 90° - 90° - 122°
= 58° (Angles at a point)
∠ACB = ∠CAD = 58° (Alternate angles)
∠ABC
= 180° - ∠CAB - ∠ACB
= 180° - 90° - 58°
= 32° (Angles sum of triangle)
(b)
∠ADC
= 180° - ∠CAD - ∠ACD
= 180° - 58° - 82°
= 40° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 40°