In the figure, YZC and BZA are right-angled triangles. CZ is parallel to BA. Find
- ∠ZAB
- ∠ZCB
(a)
∠BZC
= 360° - 90° - 90° - 126°
= 54° (Angles at a point)
∠ZBA = ∠BZC = 54° (Alternate angles)
∠ZAB
= 180° - ∠BZA - ∠ZBA
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
(b)
∠ZCB
= 180° - ∠BZC - ∠ZBC
= 180° - 54° - 82°
= 44° (Angles sum of triangle)
Answer(s): (a) 36°; (b) 44°