In the figure, ZAD and CAB are right-angled triangles. DA is parallel to CB. Find
- ∠ABC
- ∠ADC
(a)
∠CAD
= 360° - 90° - 90° - 124°
= 56° (Angles at a point)
∠ACB = ∠CAD = 56° (Alternate angles)
∠ABC
= 180° - ∠CAB - ∠ACB
= 180° - 90° - 56°
= 34° (Angles sum of triangle)
(b)
∠ADC
= 180° - ∠CAD - ∠ACD
= 180° - 56° - 87°
= 37° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 37°