In the figure, NPS and RPQ are right-angled triangles. SP is parallel to RQ. Find
- ∠PQR
- ∠PSR
(a)
∠RPS
= 360° - 90° - 90° - 123°
= 57° (Angles at a point)
∠PRQ = ∠RPS = 57° (Alternate angles)
∠PQR
= 180° - ∠RPQ - ∠PRQ
= 180° - 90° - 57°
= 33° (Angles sum of triangle)
(b)
∠PSR
= 180° - ∠RPS - ∠PRS
= 180° - 57° - 80°
= 43° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 43°
