In the figure, YZC and BZA are right-angled triangles. CZ is parallel to BA. Find
- ∠ZAB
- ∠ZCB
(a)
∠BZC
= 360° - 90° - 90° - 124°
= 56° (Angles at a point)
∠ZBA = ∠BZC = 56° (Alternate angles)
∠ZAB
= 180° - ∠BZA - ∠ZBA
= 180° - 90° - 56°
= 34° (Angles sum of triangle)
(b)
∠ZCB
= 180° - ∠BZC - ∠ZBC
= 180° - 56° - 84°
= 40° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 40°