In the figure, ABE and DBC are right-angled triangles. EB is parallel to DC. Find
- ∠BCD
- ∠BED
(a)
∠DBE
= 360° - 90° - 90° - 126°
= 54° (Angles at a point)
∠BDC = ∠DBE = 54° (Alternate angles)
∠BCD
= 180° - ∠DBC - ∠BDC
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
(b)
∠BED
= 180° - ∠DBE - ∠BDE
= 180° - 54° - 83°
= 43° (Angles sum of triangle)
Answer(s): (a) 36°; (b) 43°