In the figure, EFJ and HFG are right-angled triangles. JF is parallel to HG. Find
- ∠FGH
- ∠FJH
(a)
∠HFJ
= 360° - 90° - 90° - 124°
= 56° (Angles at a point)
∠FHG = ∠HFJ = 56° (Alternate angles)
∠FGH
= 180° - ∠HFG - ∠FHG
= 180° - 90° - 56°
= 34° (Angles sum of triangle)
(b)
∠FJH
= 180° - ∠HFJ - ∠FHJ
= 180° - 56° - 84°
= 40° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 40°