In the figure, FGK and JGH are right-angled triangles. KG is parallel to JH. Find
- ∠GHJ
- ∠GKJ
(a)
∠JGK
= 360° - 90° - 90° - 122°
= 58° (Angles at a point)
∠GJH = ∠JGK = 58° (Alternate angles)
∠GHJ
= 180° - ∠JGH - ∠GJH
= 180° - 90° - 58°
= 32° (Angles sum of triangle)
(b)
∠GKJ
= 180° - ∠JGK - ∠GJK
= 180° - 58° - 88°
= 34° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 34°