In the figure, PQT and SQR are right-angled triangles. TQ is parallel to SR. Find
- ∠QRS
- ∠QTS
(a)
∠SQT
= 360° - 90° - 90° - 124°
= 56° (Angles at a point)
∠QSR = ∠SQT = 56° (Alternate angles)
∠QRS
= 180° - ∠SQR - ∠QSR
= 180° - 90° - 56°
= 34° (Angles sum of triangle)
(b)
∠QTS
= 180° - ∠SQT - ∠QST
= 180° - 56° - 88°
= 36° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 36°