In the figure, PQT and SQR are right-angled triangles. TQ is parallel to SR. Find
- ∠QRS
- ∠QTS
(a)
∠SQT
= 360° - 90° - 90° - 121°
= 59° (Angles at a point)
∠QSR = ∠SQT = 59° (Alternate angles)
∠QRS
= 180° - ∠SQR - ∠QSR
= 180° - 90° - 59°
= 31° (Angles sum of triangle)
(b)
∠QTS
= 180° - ∠SQT - ∠QST
= 180° - 59° - 87°
= 34° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 34°