In the figure, PQT and SQR are right-angled triangles. TQ is parallel to SR. Find
- ∠QRS
- ∠QTS
(a)
∠SQT
= 360° - 90° - 90° - 120°
= 60° (Angles at a point)
∠QSR = ∠SQT = 60° (Alternate angles)
∠QRS
= 180° - ∠SQR - ∠QSR
= 180° - 90° - 60°
= 30° (Angles sum of triangle)
(b)
∠QTS
= 180° - ∠SQT - ∠QST
= 180° - 60° - 86°
= 34° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 34°
