In the figure, ABE and DBC are right-angled triangles. EB is parallel to DC. Find
- ∠BCD
- ∠BED
(a)
∠DBE
= 360° - 90° - 90° - 122°
= 58° (Angles at a point)
∠BDC = ∠DBE = 58° (Alternate angles)
∠BCD
= 180° - ∠DBC - ∠BDC
= 180° - 90° - 58°
= 32° (Angles sum of triangle)
(b)
∠BED
= 180° - ∠DBE - ∠BDE
= 180° - 58° - 88°
= 34° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 34°
