In the figure, MNR and QNP are right-angled triangles. RN is parallel to QP. Find
- ∠NPQ
- ∠NRQ
(a)
∠QNR
= 360° - 90° - 90° - 124°
= 56° (Angles at a point)
∠NQP = ∠QNR = 56° (Alternate angles)
∠NPQ
= 180° - ∠QNP - ∠NQP
= 180° - 90° - 56°
= 34° (Angles sum of triangle)
(b)
∠NRQ
= 180° - ∠QNR - ∠NQR
= 180° - 56° - 85°
= 39° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 39°