In the figure, MNR and QNP are right-angled triangles. RN is parallel to QP. Find
- ∠NPQ
- ∠NRQ
(a)
∠QNR
= 360° - 90° - 90° - 126°
= 54° (Angles at a point)
∠NQP = ∠QNR = 54° (Alternate angles)
∠NPQ
= 180° - ∠QNP - ∠NQP
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
(b)
∠NRQ
= 180° - ∠QNR - ∠NQR
= 180° - 54° - 81°
= 45° (Angles sum of triangle)
Answer(s): (a) 36°; (b) 45°
