The figure is not drawn to scale. It shows a parallelogram QRST and an isosceles triangle MQT next to it. ∠PTM = 11°. PN and ML are straight lines. Find
- ∠w
- ∠u + ∠v
- ∠v
(a)
∠w
= 180° - ∠PTM
= 180° - 11°
= 169° (Angles on a straight line)
(b)
∠u = ∠QTS (Parallelogram)
∠u + ∠v
= 180° - 11° - 57°
= 112° (Angles on a straight line)
(c)
∠MQT = ∠u (Corresponding angles)
∠MQT = ∠TMQ (Isosceles triangle)
∠u
= 180° - (∠u + ∠v)
= 180° - 112°
= 68°
∠v
= 180° - ∠u - ∠u
= 180° - 68° - 68°
= 44° (Angles sum of triangle)
Answer(s): (a) 169°; (b) 112°; (c) 44°