The figure is not drawn to scale. It shows a parallelogram LMNP and an isosceles triangle HLP next to it. ∠KPH = 11°. KJ and HG are straight lines. Find
- ∠s
- ∠q + ∠r
- ∠r
(a)
∠s
= 180° - ∠KPH
= 180° - 11°
= 169° (Angles on a straight line)
(b)
∠q = ∠LPN (Parallelogram)
∠q + ∠r
= 180° - 11° - 63°
= 106° (Angles on a straight line)
(c)
∠HLP = ∠q (Corresponding angles)
∠HLP = ∠PHL (Isosceles triangle)
∠q
= 180° - (∠q + ∠r)
= 180° - 106°
= 74°
∠r
= 180° - ∠q - ∠q
= 180° - 74° - 74°
= 32° (Angles sum of triangle)
Answer(s): (a) 169°; (b) 106°; (c) 32°