The figure is not drawn to scale. It shows a parallelogram HJKL and an isosceles triangle EHL next to it. ∠GLE = 8°. GF and ED are straight lines. Find
- ∠p
- ∠m + ∠n
- ∠n
(a)
∠p
= 180° - ∠GLE
= 180° - 8°
= 172° (Angles on a straight line)
(b)
∠m = ∠HLK (Parallelogram)
∠m + ∠n
= 180° - 8° - 53°
= 119° (Angles on a straight line)
(c)
∠EHL = ∠m (Corresponding angles)
∠EHL = ∠LEH (Isosceles triangle)
∠m
= 180° - (∠m + ∠n)
= 180° - 119°
= 61°
∠n
= 180° - ∠m - ∠m
= 180° - 61° - 61°
= 58° (Angles sum of triangle)
Answer(s): (a) 172°; (b) 119°; (c) 58°