The figure is not drawn to scale. It shows a parallelogram STUV and an isosceles triangle PSV next to it. ∠RVP = 14°. RQ and PN are straight lines. Find
- ∠y
- ∠w + ∠x
- ∠x
(a)
∠y
= 180° - ∠RVP
= 180° - 14°
= 166° (Angles on a straight line)
(b)
∠w = ∠SVU (Parallelogram)
∠w + ∠x
= 180° - 14° - 60°
= 106° (Angles on a straight line)
(c)
∠PSV = ∠w (Corresponding angles)
∠PSV = ∠VPS (Isosceles triangle)
∠w
= 180° - (∠w + ∠x)
= 180° - 106°
= 74°
∠x
= 180° - ∠w - ∠w
= 180° - 74° - 74°
= 32° (Angles sum of triangle)
Answer(s): (a) 166°; (b) 106°; (c) 32°
