In the figure, not drawn to scale, O is the centre of the semi circle and ONPQ is a rhombus. ∠OQR = 29°. Find
- ∠g
- ∠h.
(a)
OQ = OR = Radius
∠QOR
= 180° - 29° - 29°
= 122° (Isosceles triangle)
∠g = ∠QOR = 122° (Corresponding angles, NP//OQ)
(b)
∠h
= 180° - 122°
= 58° (Interior angles, PQ//NO)
Answer(s): (a) 122°; (b) 58°