In the figure, not drawn to scale, O is the centre of the semi circle and OFGH is a rhombus. ∠OHJ = 34°. Find
- ∠r
- ∠s.
(a)
OH = OJ = Radius
∠HOJ
= 180° - 34° - 34°
= 112° (Isosceles triangle)
∠r = ∠HOJ = 112° (Corresponding angles, FG//OH)
(b)
∠s
= 180° - 112°
= 68° (Interior angles, GH//FO)
Answer(s): (a) 112°; (b) 68°