In the figure, not drawn to scale, O is the centre of the semi circle and OPQR is a rhombus. ∠ORS = 34°. Find
- ∠q
- ∠r.
(a)
OR = OS = Radius
∠ROS
= 180° - 34° - 34°
= 112° (Isosceles triangle)
∠q = ∠ROS = 112° (Corresponding angles, PQ//OR)
(b)
∠r
= 180° - 112°
= 68° (Interior angles, QR//PO)
Answer(s): (a) 112°; (b) 68°