In the figure, not drawn to scale, O is the centre of the semi circle and OZAB is a rhombus. ∠OBC = 34°. Find
- ∠h
- ∠i.
(a)
OB = OC = Radius
∠BOC
= 180° - 34° - 34°
= 112° (Isosceles triangle)
∠h = ∠BOC = 112° (Corresponding angles, ZA//OB)
(b)
∠i
= 180° - 112°
= 68° (Interior angles, AB//ZO)
Answer(s): (a) 112°; (b) 68°