In the figure, not drawn to scale, O is the centre of the semi circle and OZAB is a rhombus. ∠OBC = 35°. Find
- ∠q
- ∠r.
(a)
OB = OC = Radius
∠BOC
= 180° - 35° - 35°
= 110° (Isosceles triangle)
∠q = ∠BOC = 110° (Corresponding angles, ZA//OB)
(b)
∠r
= 180° - 110°
= 70° (Interior angles, AB//ZO)
Answer(s): (a) 110°; (b) 70°