Question
P6.AN.NK.17051718-A1
In the figure, EFGH is a parallelogram. GE = GJ = GK. EK and GJ are straight lines. ∠EJG = 75° and ∠EKG = 30°. Find ∠EFG.
3 m
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Primary 6 ANGLES P6.AN.NK.17051718

17 May 2024, 09:54 PM

In the figure, EFGH is a parallelogram. GE = GJ = GK. EK and GJ are straight lines. ∠EJG = 75° and ∠EKG = 30°. Find ∠EFG.
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