The figure is not drawn to scale. DE//GF and FE//HD. Triangles DHE and EFG are isosceles triangles. Find
- ∠g
- ∠h.
(a)
∠EFG = ∠EDH = 78° (FE//HD, ED//FG)
∠DEH
= (180° - 78°) ÷ 2
= 102° ÷ 2
= 51° (Isosceles triangle)
∠FEG
= 180° - 78° - 78°
= 24° (Isosceles triangle)
∠g
= 180° - 78° - 51° - 24°
= 27° (Interior angles, ED//FG)
(b)
∠h
= 180° - 24° - 27°
= 129° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 129°