The figure is not drawn to scale. AB//DC and CB//EA. Triangles AEB and BCD are isosceles triangles. Find
- ∠n
- ∠p.
(a)
∠BCD = ∠BAE = 76° (CB//EA, BA//CD)
∠ABE
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
∠CBD
= 180° - 76° - 76°
= 28° (Isosceles triangle)
∠n
= 180° - 76° - 52° - 28°
= 24° (Interior angles, BA//CD)
(b)
∠p
= 180° - 30° - 24°
= 126° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 126°