The figure is not drawn to scale. EF//HG and GF//JE. Triangles EJF and FGH are isosceles triangles. Find
- ∠g
- ∠h.
(a)
∠FGH = ∠FEJ = 70° (GF//JE, FE//GH)
∠EFJ
= (180° - 70°) ÷ 2
= 110° ÷ 2
= 55° (Isosceles triangle)
∠GFH
= 180° - 70° - 70°
= 40° (Isosceles triangle)
∠g
= 180° - 70° - 55° - 40°
= 15° (Interior angles, FE//GH)
(b)
∠h
= 180° - 27° - 15°
= 138° (Angles sum of triangle)
Answer(s): (a) 15°; (b) 138°