Question
In the figure, not drawn to scale, CEFG is a parallelogram and CDH is an isosceles triangle. GHED is a straight line. ∠EFG = 97°, ∠CEH = 51° and ∠ECD = 14°. Find ∠GCH.
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In the figure, not drawn to scale, CEFG is a parallelogram and CDH is an isosceles triangle. GHED is a straight line. ∠EFG = 97°, ∠CEH = 51° and ∠ECD = 14°. Find ∠GCH.