In the figure, not drawn to scale, DFGH is a parallelogram and DEJ is an isosceles triangle. HJFE is a straight line. ∠FGH = 101°, ∠DFJ = 53° and ∠FDE = 12°. Find ∠HDJ.
3 m
In the figure, not drawn to scale, DFGH is a parallelogram and DEJ is an isosceles triangle. HJFE is a straight line. ∠FGH = 101°, ∠DFJ = 53° and ∠FDE = 12°. Find ∠HDJ.
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Ischool Pte Ltd
Date:28 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051727
Student:
Class:
Level:
School:
In the figure, not drawn to scale, DFGH is a parallelogram and DEJ is an isosceles triangle. HJFE is a straight line. ∠FGH = 101°, ∠DFJ = 53° and ∠FDE = 12°. Find ∠HDJ.
(3 m)
Ischool Pte Ltd
Date:
28 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051727
Student:
Class:
Level:
School:
In the figure, not drawn to scale, DFGH is a parallelogram and DEJ is an isosceles triangle. HJFE is a straight line. ∠FGH = 101°, ∠DFJ = 53° and ∠FDE = 12°. Find ∠HDJ.
In the figure, not drawn to scale, DFGH is a parallelogram and DEJ is an isosceles triangle. HJFE is a straight line. ∠FGH = 101°, ∠DFJ = 53° and ∠FDE = 12°. Find ∠HDJ.
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ISchool Pte Ltd
Date:28 Jun 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051727-A1
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