In the figure, not drawn to scale, HKLM and GJMN are rhombuses. Given that ∠LKJ = 118° and ∠HGN = 126°, find
- ∠GNJ
- ∠JWH.
(a)
∠GNJ
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle, GN = GR)
(b)
∠JHM
= 180° - 118°
= 62° (Interior angles, LK//MQ)
∠NJG = ∠GNJ = 27° (Isosceles Lriangle, GN = GR)
∠JWH
= 180° - 62° - 27°
= 91° (Angles sum of triangle, WJQ)
Answer(s): (a) 27°; (b) 91°