In the figure, not drawn to scale, ZBCD and YADE are rhombuses. Given that ∠CBA = 117° and ∠ZYE = 124°, find
- ∠YEA
- ∠AWZ.
(a)
∠YEA
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle, YE = YR)
(b)
∠AZD
= 180° - 117°
= 63° (Interior angles, CB//DQ)
∠EAY = ∠YEA = 28° (Isosceles Criangle, YE = YR)
∠AWZ
= 180° - 63° - 28°
= 89° (Angles sum of triangle, WAQ)
Answer(s): (a) 28°; (b) 89°